hsack 0 n = n + 1
ack m 0 = ack (m-1) 1
ack m n = ack (m-1) $ ack m (n-1)
第1x∖第2y | 0 | 1 | 2 | 3 | 4 | 5 | ⋯ |
0 | 1 | 2 | 3 | 4 | 5 | 6 | ⋯ |
1 | 2 | 3 | 4 | 5 | 6 | 7 | ⋯ |
2 | 3 | 5 | 7 | 9 | 11 | 13 | ⋯ |
3 | 5 | 13 | 29 | 61 | 125 | 253 | ⋯ |
4 | 13 | 65533 | 2^65536−3 | 巨大 | 巨大 | 巨大 | ⋯ |
5 | 65533 | 巨大 | 巨大 | 巨大 | 巨大 | 巨大 | ⋯ |
... | ... | ... | ... | ... | ... | .. | ... |
ack m n
= hyper(m,2,n+3) -3